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RE: Dont assume others are evil

in #freedom6 years ago

I was called to perform a provably fair random drawing for @reversed-bidbot!

There are a 969 tickets participating in this round.























The merkle root of the block in which this post will appear determines the winner. @hdu holds tickets number 0 - 0 @imisstheoldkanye holds tickets number 1 - 2 @inversionistam holds tickets number 3 - 10 @bukiland holds tickets number 11 - 12 @luegenbaron holds tickets number 13 - 41 @freebornsociety holds tickets number 42 - 58 @kabir88 holds tickets number 59 - 456 @rubinka holds tickets number 457 - 457 @deirdyweirdy holds tickets number 458 - 482 @frdem3dot0 holds tickets number 483 - 514 @wordsword holds tickets number 515 - 533 @spe3dy123 holds tickets number 534 - 534 @hiblockchain holds tickets number 535 - 536 @reversed-bidbot holds tickets number 537 - 541 @steem-raffle holds tickets number 542 - 564 @curatorbot holds tickets number 565 - 565 @zoidsoft holds tickets number 566 - 677 @mattclarke holds tickets number 678 - 847 @klevn holds tickets number 848 - 856 @intothewild holds tickets number 857 - 896 @rpgbuilders holds tickets number 897 - 898 @freebornangel holds tickets number 899 - 963 @general.guy holds tickets number 964 - 968

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The block in which the above post is included has a merkle root of e481bf76f90975023612a1b285214456e5bb77ec.
To find the winner we:

  1. Convert the merkle root into base 10:
    e481bf76f90975023612a1b285214456e5bb77ec = 1304543370809404999627548638503015781185460336620.
  2. Compute the residual after dividing by the number of tickets: 1304543370809404999627548638503015781185460336620 mod 969 = 709.
  3. This is the winning ticket, held by @mattclarke.

Congratulations!

Interesting, how did I manage to get so many raffle tickets @steem-raffle?