4?
3^3 is 27 but 27^0 is still 1. 3^0 = 1 also and 3^1 = 3 so you get 3+1 = 4. But it's been a while since I've mathed so I'm probably forgetting something with regards to order of operations and exponents, lol.
4?
3^3 is 27 but 27^0 is still 1. 3^0 = 1 also and 3^1 = 3 so you get 3+1 = 4. But it's been a while since I've mathed so I'm probably forgetting something with regards to order of operations and exponents, lol.
Correct, bOOm !
It's true there is is an order of precedence for mathematical operators. It's also true that parentheses override normal operator precedence, form the innermost set of parentheses out. I forgot that detail earlier.