I think I can get eleven. Start with drawing a diameter, and then another diameter that is the first's perpendicular bisector. Continue by drawing a line 45 degrees tilted from the first diameter but shift it slightly down to prevent it from crossing the center. Now draw a line tilted about 70 degrees from the first diameter and again lower it so that it crosses all three past lines making eleven sections. (These don't have to be exact). 
You are viewing a single comment's thread from:
Yeah, this also seems a possible solution - actually this was the one I had in mind...